题目内容
请你计算下面各题,能简算的简算.
63×(
|
1
|
分析:(1)运用乘法分配律解答,
(2)化带分数为假分数,依据积不变性质约分即可解答.
(2)化带分数为假分数,依据积不变性质约分即可解答.
解答:解:(1)63×(
-
)÷
,
=(63×
-63×
)÷
,
=(90-70)÷
,
=20÷
,
=200;
(2)1
×1
×1
×1
×1
,
=
×
×
×
×
,
=1
.
| 10 |
| 7 |
| 10 |
| 9 |
| 1 |
| 10 |
=(63×
| 10 |
| 7 |
| 10 |
| 9 |
| 1 |
| 10 |
=(90-70)÷
| 1 |
| 10 |
=20÷
| 1 |
| 10 |
=200;
(2)1
| 1 |
| 6 |
| 1 |
| 7 |
| 1 |
| 8 |
| 1 |
| 9 |
| 1 |
| 10 |
=
| 7 |
| 6 |
| 8 |
| 7 |
| 9 |
| 8 |
| 10 |
| 9 |
| 11 |
| 10 |
=1
| 5 |
| 6 |
点评:解答本题要注意各数的特点,再根据它们的特点,选择并运用正确的简便算法.
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