题目内容
解下列方程.
x+
x=42
(
+
)x=
×5-12x=1.
x+
| 7 |
| 8 |
(
| 5 |
| 8 |
| 5 |
| 6 |
| 7 |
| 10 |
| 4 |
| 5 |
(1)x+
x=42
x÷
=42÷
x=22.4;
(2)(
+
)x=
x=
,
x÷
=
÷
,
x=
;
(3)
×5-12x=1
4-12x=1,
4-12x+12x=1+12x,
1+12x=4,
1+12x-1=4-1,
12x=3,
12x÷12=3÷12,
x=
.
| 7 |
| 8 |
| 15 |
| 8 |
| 15 |
| 8 |
| 15 |
| 8 |
x=22.4;
(2)(
| 5 |
| 8 |
| 5 |
| 6 |
| 7 |
| 10 |
| 35 |
| 24 |
| 7 |
| 10 |
| 35 |
| 24 |
| 35 |
| 24 |
| 7 |
| 10 |
| 35 |
| 24 |
x=
| 12 |
| 25 |
(3)
| 4 |
| 5 |
4-12x=1,
4-12x+12x=1+12x,
1+12x=4,
1+12x-1=4-1,
12x=3,
12x÷12=3÷12,
x=
| 1 |
| 4 |
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