题目内容
| 3 |
| 5 |
| 4 |
| 5 |
| 4 |
| 7 |
| 21 |
| x |
| 32 |
| 8 |
| 4.2 |
| 15 |
| 5.6 |
| x |
6:x=
| 3 |
| 11 |
| 5 |
| 11 |
分析:根据比例的基本性质,先把比例式化成一元一次方程的形式,再利用等式的性质即可解答.
解答:解:(1)
:x=
:
,
x=
×
,
x×
=
×
,
x=
,
(2)
=
,
32x=21×8,
32x÷32=168÷32,
x=5.25,
(3)
=
,
4.2x=15×5.6,
4.2x÷4.2=84÷4.2,
x=20,
(4)6:x=
:
,
x=
×6,
x×
=
×
,
x=10.
| 3 |
| 5 |
| 4 |
| 5 |
| 4 |
| 7 |
| 4 |
| 5 |
| 3 |
| 5 |
| 4 |
| 7 |
| 4 |
| 5 |
| 5 |
| 4 |
| 12 |
| 35 |
| 5 |
| 4 |
x=
| 3 |
| 7 |
(2)
| 21 |
| x |
| 32 |
| 8 |
32x=21×8,
32x÷32=168÷32,
x=5.25,
(3)
| 4.2 |
| 15 |
| 5.6 |
| x |
4.2x=15×5.6,
4.2x÷4.2=84÷4.2,
x=20,
(4)6:x=
| 3 |
| 11 |
| 5 |
| 11 |
| 3 |
| 11 |
| 5 |
| 11 |
| 3 |
| 11 |
| 11 |
| 3 |
| 30 |
| 11 |
| 11 |
| 3 |
x=10.
点评:此题考查了利用比例的基本性质解比例的方法.
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