题目内容
递等式计算.(能简算的要简算,并写出必要的过程).
①0.125×0.25×8×4
②(1-0.05)÷1.9+0.1
③
×
-
×
④
÷23+
×
⑤
×[1-(
-
)]
⑥3.6-2.8+7.4-7.2.
解:①0.125×0.25×8×4,
=0.125×8×(0.25×4),
=1×1,
=1;
②(1-0.05)÷1.9+0.1
=0.95÷1.9+0.1,
=0.5+0.1,
=0.6;
③
×
-
×
=
-
,
=
,
=
;
④
÷23+
×
=
×
+
×
,
=
×(
),
=
×1,
=
;
⑤
×[1-(
-
)]
=
×(1-
),
=
×
,
=
;
⑥3.6-2.8+7.4-7.2.
=3.6+7.4-(2.8+7.2),
=11-10,
=1.
分析:①利用乘法交换律及结合律计算,
②、③、⑤根据四则混合运算的运算顺序计算即可.
④將算式中的÷23变成×
后,利用乘法分配律进行计算;
⑥將算式变为3.6+7.4-2.2-7.2再简算.
点评:此题是考查四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.
=0.125×8×(0.25×4),
=1×1,
=1;
②(1-0.05)÷1.9+0.1
=0.95÷1.9+0.1,
=0.5+0.1,
=0.6;
③
=
=
=
④
=
=
=
=
⑤
=
=
=
⑥3.6-2.8+7.4-7.2.
=3.6+7.4-(2.8+7.2),
=11-10,
=1.
分析:①利用乘法交换律及结合律计算,
②、③、⑤根据四则混合运算的运算顺序计算即可.
④將算式中的÷23变成×
⑥將算式变为3.6+7.4-2.2-7.2再简算.
点评:此题是考查四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.
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