摘要:(x1-x2)(x1+x2)-2(y1-y2)(y1+y2)=0,∵x1≠x2∴(x1+x2)+2 (y1+y2)=0

网址:http://m.1010jiajiao.com/timu_id_567644[举报]

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网