摘要:(Ⅱ)若PC//平面FBD,求二面角A-FD-B的余弦值.
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(1)H为BD上一点,且AH⊥平面PDB,求证:平面ABCD⊥平面APB;
(2)若PC=
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(2013•嘉兴二模)如图,在△ABC中,∠C=90°,AC=BC=3a,点P在AB上,PE∥BC交AC于E,PF∥AC交BC于F.沿PE将△APE翻折成△A′PE,使平面A′PE⊥平面ABC;沿PF将△BPF翻折成△B′PF,使平面B′PF⊥平面ABC.
(Ⅰ)求证:B′C∥平面A′PE.
(Ⅱ)若AP=2PB,求二面角A′-PC-E的平面角的正切值.

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(Ⅰ)求证:B′C∥平面A′PE.
(Ⅱ)若AP=2PB,求二面角A′-PC-E的平面角的正切值.
(Ⅰ)求证:BD⊥PC;
(Ⅱ)若PA=AB,求二面角A-PD-B的余弦值.