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(Ⅰ)写出{an}和{bn}的通项公式;
(Ⅱ)试求满足不等式≤-160b2的正整数m.
已知{an}是等差数列,a1=-393,a2+a3=-768,{bn}是公比为q(0<q<1)的无穷等比数列,b1=2,且{bn}的各项和为20.