摘要:4.已知a + b + c =0, |a| = 1,|b| = 2,|c| =,a·b+b·c+c·a的值为( ) A.7 B. C.– 7 D.– [解析]D.∵(a + b + c)2 =|a|2 + |b|2 + |c|2 + 2a·b+2b·c+2a·c=1+4+2+2(a·b+b·c+c·a)=0,∴a·b+b·c+c·a =–.故选D.
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