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若函数f(x)存在反函数f-1(x),且函数f(x)图象在点(x0,f(x0))处的切线方程为2x-y+1=0,则函数f-1(x)的图象在点(f(x0),x0)处的切线方程为
2x-y+1=0
x―2y―1=0
x-2y+1=0
2x+y-1=0