摘要：089]解:(1)圆心在坐标原点.圆的半径为1. 点的坐标分别为 抛物线与直线交于点.且分别与圆相切于点和点. ．······························································································· 2分 点在抛物线上.将的坐标代入 .得: 解之.得: 抛物线的解析式为:．······································································ 4分 (2) 抛物线的对称轴为. ．···················· 6分 连结. .. 又. . ．····································································· 8分 (3)点在抛物线上．································································································ 9分 设过点的直线为:. 将点的坐标代入.得:. 直线为:．······················································································ 10分 过点作圆的切线与轴平行.点的纵坐标为. 将代入.得:． 点的坐标为.··························································································· 11分 当时.. 所以.点在抛物线上．···································································· 12分 说明:解答题各小题中只给出了1种解法.其它解法只要步骤合理.解答正确均应得到相应的分数．

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