摘要:n=0.1L×12mol/L-n(气)-2n(Cu2+)余=0.1×12-0.4-2×0.2×0.1=0.76mol

网址:http://m.1010jiajiao.com/timu_id_236637[举报]

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网