摘要:A 点拨:∵x2≥0,│x│≥0,∴x2-4│x│+3=0的解就是方程│x│2-4│x│+3=0的解,=0,x=±3或x=±1.
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下列各式从左边到右边的变形中,是分解因式的有( )
①x2-y2-1=(x+y)(x-y)-1 ②x2+x=x(x+1)
③(x-y)2=x2-2xy+y2 ④x2-9y2=(x+3y)(x-3y)
①x2-y2-1=(x+y)(x-y)-1 ②x2+x=x(x+1)
③(x-y)2=x2-2xy+y2 ④x2-9y2=(x+3y)(x-3y)
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