摘要:13.平行四边形ABCD中.E为BC上一点.且.AE交BD于点F.BF=5.则DF= .
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(1)求证:△ADF∽△DEC;
(2)若AB=4,AD=3
| 3 |
(1)求证:AE⊥DE.
(2)过A、D、E三点作圆交AB于F,连DF交AE于G,若
| AB |
| AE |
| 5 |
| 8 |
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| 3 |
| AB |
| AE |
| 5 |
| 8 |