摘要:当 时..且递减,当 时..且递减,故
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在R+上的递减函数f(x)同时满足:(1)当且仅当x∈M?R+时,函数值f(x)的集合为[0,2];(2)f(
)=1;(3)对M中的任意x1、x2都有f(x1•x2)=f(x1)+f(x2);(4)y=f(x)在M上的反函数为y=f-1(x).
(1)求证:
∈M,但
∉M;
(2)求证:f-1(x1)•f-1(x2)=f-1(x1+x2);
(3)解不等式:f-1(x2-x)•f-1(x-1)≤
.
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| 1 |
| 2 |
(1)求证:
| 1 |
| 4 |
| 1 |
| 8 |
(2)求证:f-1(x1)•f-1(x2)=f-1(x1+x2);
(3)解不等式:f-1(x2-x)•f-1(x-1)≤
| 1 |
| 2 |
已知{an}为递减的等比数列,且{a1,a2,a3}?{-4,-3,-2,0,1,2,3,4}.
(Ⅰ)求数列{an}的通项公式;
(Ⅱ)当bn=
an时,求证:b1+b2+b3+…+b2n-1<
.
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(Ⅰ)求数列{an}的通项公式;
(Ⅱ)当bn=
| 1-(-1)n |
| 2 |
| 16 |
| 3 |