摘要:DD1平面D1DP∴平面D1DP⊥平面A1B1C1D1,又平面D1DP∩平面A1B1C1D1=D1P,过C1作C1H⊥D1P于H,则C1H⊥平面D1DP.∴C1H的长为点C1到平面D1DP的距离. 连结C1P.并在D1C1上取点Q.使PQ∥B1C1.在△D1PC1中,
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(Ⅰ)求证:B1B∥平面D1AC;
(Ⅱ)求二面角B1-AD1-C的余弦值.
(Ⅰ)求证:A1C1与AC共面,B1D1与BD共面;
(Ⅱ)求证:平面A1ACC1⊥平面B1BDD1;
(Ⅲ)求二面角A-BB1-C的大小(用反三角函数值圾示). 查看习题详情和答案>>
(Ⅰ)求证:B1B∥平面D1AC;
(II)求平面B1AD1与平面CAD1夹角的余弦值.