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若直线x-y+m=0与圆x2+y2-2x-2=0相切,则实数m的值是
或-
-或3
或-3
-3或3
(A)1,-1
(B)2,-2
(C)1
(D)-1
若直线(1+a)x+y+1=0与圆x2+y2-2x=0相切,则a的值是( )
A.1或-1 B.2或-2 C.1 D.-1