摘要:28.如图.四边形ABCD中.AC⊥AB.∠ADB=∠ACB.过点A作AE⊥BC.垂足为E.交BD于点F. (1)求证:AB2=BF·BD, (2)求证:∠BDC=90°.
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(本题满分8分)如图,四边形ABCD内接于⊙O,AB为⊙O的直径,C为BD弧的中点,AC、BD交于点E.
(1)求证:△CBE∽△CAB;
(2)若S△CBE∶S△CAB=1∶4,求sin∠ABD的值.
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