摘要:27. )已知等腰梯形ABCD中AD∥BC.AB=CD.AE∥DC交BC于E.G为AE中点.DG延长线交BC于F (1)说明:△AGD≌△EGF (2)若AD+BF=DC. ①说明:AE⊥BG ②求∠C的度数.
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(1)用直尺和圆规作出∠BAD的平分线AE,交BC于点E,(保留作图痕迹,不要求写作法);
(2)求证:四边形AECD是平行四边形.
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