摘要:8.设Sn是公差不为0的等差数列{an}的前n项和.且S1.S2.S4成等比数列.则等于 ( ) A.1 B.2 C.3 D.4 答案:C 解析:设等差数列{an}首项为a1.公差为d≠0.因为S1.S2.S4成等比数列.所以a1·(4a1+6d)=(2a1+d)2.解得2a1=d.因此=3.选择C.
网址:http://m.1010jiajiao.com/timu3_id_563386[举报]