摘要:13.如右图所示.已知PA与⊙O相切. A为切点.PBC为割线..弦CD∥AP.AD.BC相交于E点.F为CE上一点.且DE2=EF·EC. (1)求证:∠P=∠EDF, (2)求证:CE·EB=EF·EP, (3)若CE ∶BE=3∶2.DE=6.EF= 4.求PA的长
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| OD |
| DB |
| OA |
| a |
| OB |
| b |
(1)用
| a |
| b |
| OC |
| DC |
(2)若
| OE |
| OA |
| 1 |
| 4 |
| 1 |
| 12 |
| 1 |
| 12 |