摘要:7.设A=1+2x4.B=2x3+x2.x∈R.则A.B的大小关系是 . 解析:∵A-B=1+2x4-2x3-x2=2x3(x-1)-(x2-1) =(x-1)(2x3-x-1) =(x-1)2(2x2+2x+1). ∵(x-1)2≥0,2x2+2x+1>0. ∴A-B≥0.即A≥B. 答案:A≥B
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