摘要:已知抛物线y2=4x及点A(1,1).若过点A的直线被此抛物线截得的弦PQ恰以A为中点.则直线PQ的方程为 A.4x-y-3=0 B.2x-y+1=0 C.4x-y+3=0 D.2x-y-1=0

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