摘要:17.解:(1)∵点A在反比例函数的图象上.∴. -------1分 ∴反比例函数的解析式为.···························································· 2分 ∵点B在反比例函数的图象上. ∴.∴.··········································································· 3分 ∴点B的坐标为. ∵点A.点B在一次函数的图象上. ∴.∴ ∴一次函数的解析式为······························································ 5分

网址:http://m.1010jiajiao.com/timu3_id_471499[举报]

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网