摘要:已知等差数列{an}的前n项和为18.前三项和S3=1.an-2+an-1+an=3.则n的值是 ( ) A.9 B.21 C.27 D.30
网址:http://m.1010jiajiao.com/timu3_id_4462465[举报]
已知等差数列{an}的前n项和为Sn,公差d≠0,a1=1,且a1,a2,a7成等比数列.
(1)求数列{an}的前n项和Sn;
(2)设bn=
,数列{bn}的前n项和为Tn,求证:2Tn-9bn-1+18>
(n>1).
查看习题详情和答案>>
(1)求数列{an}的前n项和Sn;
(2)设bn=
| 2Sn |
| 2n-1 |
| 64bn |
| (n+9)bn+1 |