摘要:20. 化学反应N2+3H2 = 2NH3的能量变化如图所示.该反应的热化学方程式是 A.N2(g)+3H2(g) = 2NH3(l), ⊿H=2(a-b-c)KJ/mol B.N2(g)+3H2(g) = 2NH3(g) , ⊿H = 2(b-a) KJ/mol C.N2(g)+H2(g) = NH3(l) , ⊿H = (b+c-a) KJ/mol D.N2(g)+H2(g) =NH3(g) , ⊿H = (a+b) KJ/mol 第II卷

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