ÌâÄ¿ÄÚÈÝ
ÈçͼËùʾ£¬Ò»¸öÖÊÁ¿m=10-6kg£¬µçÁ¿q=+2.0cµÄ΢Á££¬Óɾ²Ö¹¿ªÊ¼³ö·¢£¬¼ÓËÙµçѹU¼Ó=105V£¬´øµç΢Á£´¹Ö±½øÈëÆ«×ªµç³¡ÖУ¬°å³¤l=20cm£¬Á½°å¼ä¾àÀëd=4cm£¬Á½°å¼äƫתµçѹUÆ«=4¡Á103V£¨²»¼ÆÖØÁ¦£©£¬ÊÔÇó£º
£¨1£©´øµçÁ£×ÓÀ뿪ƫתµç³¡Ê±²àÒÆÊǶàÉÙ£¿
£¨2£©È«¹ý³ÌÖе糡Á¦¶Ô´øµçÁ£×Ó×ö¹¦Îª¶àÉÙ£¿
£¨3£©ÈôÔÚÆ«×ªµç³¡ÓÒ²à¾àÀëΪS=20cm´¦£¬·ÅÒ»ÊúÖ±Ó«¹âÆÁ£¬Ôò´øµçÁ£×Ó´òÔÚÓ«¹âÆÁÉϵÄλÖþàÖÐÐÄOµÄ¾àÀ룿

£¨1£©´øµçÁ£×ÓÀ뿪ƫתµç³¡Ê±²àÒÆÊǶàÉÙ£¿
£¨2£©È«¹ý³ÌÖе糡Á¦¶Ô´øµçÁ£×Ó×ö¹¦Îª¶àÉÙ£¿
£¨3£©ÈôÔÚÆ«×ªµç³¡ÓÒ²à¾àÀëΪS=20cm´¦£¬·ÅÒ»ÊúÖ±Ó«¹âÆÁ£¬Ôò´øµçÁ£×Ó´òÔÚÓ«¹âÆÁÉϵÄλÖþàÖÐÐÄOµÄ¾àÀ룿
£¨1£©¼ÓËٵ糡ÖлñµÃv0µÄËÙ¶È£¬ÔòÓУº
qU¼Ó=
m
¢Ù
´¹Ö±½øÈëÆ«×ªµç³¡×öÀàÆ½Å×Ô˶¯£¬²àÒÆÎªy£¬Ôò
y=
£¨
£©2 ¢Ú
¢Ù¢ÚÁªÁ¢½âµÃ£ºy=
=
m=0.01m£»
£¨2£©ÔÚ¼ÓËٵ糡Öе糡Á¦×öµÄ¹¦ÎªW1£¬
W1=qU¼Ó ¢Û
ÔÚÆ«×ªµç³¡Öе糡Á¦×öµÄ¹¦ÎªW2£¬
W2=q
y ¢Ü
ÓÉ¢Û¡¢¢ÜµÃ£ºW=W1+W2=qU¼Ó+q
y=0.2¡Á£¨105+
£©J=2.02¡Á104J£»
£¨3£©Éè´øµçÁ£×Ó´òÔÚÓ«¹âÆÁÉϵÄPµã£¬ÀûÓôøµçÁ£×ÓÀ뿪ƫתµç³¡Ê±£¬Ëٶȵķ´ÏòÑÓ³¤Ïß½»ÓÚÁ½°å¼äÖÐÖáÏßµÄ
´¦£¬ÔòÓÉÏàËÆÈý½ÇÐεãº
=
»¯¼òºó
=£¨1+
£©y=£¨1+
£©¡Á0.01m=0.03m
´ð£º
£¨1£©´øµçÁ£×ÓÀ뿪ƫתµç³¡Ê±²àÒÆÊÇ0.01m£®
£¨2£©È«¹ý³ÌÖе糡Á¦¶Ô´øµçÁ£×Ó×ö¹¦Îª2.02¡Á104J£®
£¨3£©´øµçÁ£×Ó´òÔÚÓ«¹âÆÁÉϵÄλÖþàÖÐÐÄOµÄ¾àÀëΪ0.03m£®
qU¼Ó=
| 1 |
| 2 |
| v | 20 |
´¹Ö±½øÈëÆ«×ªµç³¡×öÀàÆ½Å×Ô˶¯£¬²àÒÆÎªy£¬Ôò
y=
| 1 |
| 2 |
| qUÆ« |
| md |
| l |
| v0 |
¢Ù¢ÚÁªÁ¢½âµÃ£ºy=
| Uƫl2 |
| 4dU¼Ó |
| 4¡Á103¡Á0£®22 |
| 4¡Á0.04¡Á105 |
£¨2£©ÔÚ¼ÓËٵ糡Öе糡Á¦×öµÄ¹¦ÎªW1£¬
W1=qU¼Ó ¢Û
ÔÚÆ«×ªµç³¡Öе糡Á¦×öµÄ¹¦ÎªW2£¬
W2=q
| UÆ« |
| d |
ÓÉ¢Û¡¢¢ÜµÃ£ºW=W1+W2=qU¼Ó+q
| UÆ« |
| d |
| 4¡Á103¡Á0.01 |
| 0.04 |
£¨3£©Éè´øµçÁ£×Ó´òÔÚÓ«¹âÆÁÉϵÄPµã£¬ÀûÓôøµçÁ£×ÓÀ뿪ƫתµç³¡Ê±£¬Ëٶȵķ´ÏòÑÓ³¤Ïß½»ÓÚÁ½°å¼äÖÐÖáÏßµÄ
| l |
| 2 |
| y | ||
|
| ||
|
»¯¼òºó
| . |
| OP |
| 2S |
| l |
| 2¡Á0.2 |
| 0.2 |
´ð£º
£¨1£©´øµçÁ£×ÓÀ뿪ƫתµç³¡Ê±²àÒÆÊÇ0.01m£®
£¨2£©È«¹ý³ÌÖе糡Á¦¶Ô´øµçÁ£×Ó×ö¹¦Îª2.02¡Á104J£®
£¨3£©´øµçÁ£×Ó´òÔÚÓ«¹âÆÁÉϵÄλÖþàÖÐÐÄOµÄ¾àÀëΪ0.03m£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿