ÌâÄ¿ÄÚÈÝ

5£®ÓÐÒ»¸öÖ±Á÷µç¶¯»ú£¬ÄÚ×è²»±ä£¬µ±Á½¶Ë¼Ó0.2Vµçѹʱµç»ú²»×ª£¬²âµÃÁ÷¹ýµç¶¯»úµÄµçÁ÷ÊÇ0.4A£»Èôµç¶¯»úÁ½¶Ë¼Ó2.0Vµçѹʱ£¬Õý³£¹¤×÷£¬´ËʱµÄµçÁ÷ÊÇ1.0A£¬´Ëʱ£¬µç¶¯»úµÄÊä³ö¹¦ÂÊÊÇP³ö£ºÈç¹ûÔڵ綯»úÕý³£¹¤×÷ʱ£¬µç¶¯»úͻȻ°Ñ¿¨×¡²»×ªÁË£¬µç¶¯»úµÄ·¢Èȹ¦ÂÊÊÇPÈÈ£¬ÔòÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®µç¶¯»úµÄµç×èΪ2¦¸
B£®P³öΪ2W
C£®µç¶¯»úÕý³£¹¤×÷ʱµÄÏûºÄµÄµç¹¦ÂÊΪ2W
D£®PÈÈΪ4W

·ÖÎö A¡¢µ±µç»ú²»×ªÊ±£¬Æäµç·ÊÇ´¿µç×èµç·£¬ÓÉÅ·Ä·¶¨ÂÉÇó³öµç»úµÄÄÚ×裻
BC¡¢µ±µç»úÕý³£¹¤×÷ʱ£¬Æäµç·ÊÇ·Ç´¿µç×èµç·£¬µç¹¦ÂÊP×Ü=UI£¬Êä³ö¹¦ÂÊP³ö=P×Ü-PÄÚ=UI-I2r£¬´úÈëÇó½âµç¶¯»úÕý³£¹¤×÷ʱµÄÊä³ö¹¦ÂÊ£»
D¡¢µç¶¯»úµÄת×ÓͻȻ±»¿¨×¡Ê±£¬µç¶¯»úµÄ·¢Èȹ¦ÂÊPÈÈ=$\frac{{U}^{2}}{r}$£®

½â´ð ½â£ºA¡¢µ±µç»ú²»×ªÊ±£¬ÓÉÅ·Ä·¶¨ÂÉ£¬µç»úµÄÄÚ×èΪ£ºr=$\frac{{U}_{1}}{{I}_{1}}$=$\frac{0.2A}{0.4A}$=0.5¦¸£¬¹ÊA´íÎó£»
C¡¢µç¶¯»úÕý³£¹¤×÷ʱ£¬µç¹¦ÂÊ£ºP×Ü=U2I2=2¡Á1=2W£¬¹ÊCÕýÈ·£»
B¡¢µç¶¯»úÕý³£¹¤×÷ʱ£¬Êä³ö¹¦ÂÊ£ºP³ö=P×Ü-PÄÚ=UI-I2r=2-12¡Á0.5=1.5W£¬¹ÊB´íÎó£»
D¡¢µç¶¯»úµÄת×ÓͻȻ±»¿¨×¡Ê±£¬´ËʱÏ൱ÓÚ´¿µç×裬·¢Èȹ¦ÂÊΪ£º
${P_ÈÈ}=\frac{U^2}{r}=\frac{2^2}{0.5}W=8W$
¹ÊD´íÎó£»
¹ÊÑ¡£ºC

µãÆÀ ¶ÔÓڵ綯»úµç·£¬ÒªÕýÈ·Çø·ÖÊÇ´¿µç×èµç·£¬»¹ÊÇ·Ç´¿µç×èµç·£¬¹Ø¼ü¿´×ª×ÓÊÇ·ñת¶¯£¬µçÄÜÊÇ·ñÈ«²¿×ª»¯ÎªÄÚÄÜ£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø