题目内容


某同学探究弹力与弹簧伸长量的关系.                                                                   

①将弹簧悬挂在铁架台上,将刻度尺固定在弹簧一侧,弹簧轴线和刻度尺都应在         方向(填 “水平”或“竖直”)        

                  L0     Lx     L1     L2     L3   L4     L5     L6

数值(cm)        25.35        27.35      29.35        31.30    33.4 35.35      37.40      39.30

②弹簧自然悬挂,静止时,长度记为L0,弹簧下端挂上砝码盘时,长度记为Lx;在砝码盘中每次增加10g砝码,弹簧长度依次记为L1至L6,数据如上表:表中有一个数值记录不规范,代表符号为              .由表可知所用刻度尺的最小刻度为                                                                                                               

③如图是该同学根据表中数据作的图,纵轴是砝码的质量,横轴是弹簧长度与    LX 的差值(填“L0或LX”).         

④由图可知弹簧的劲度系数为                                                                   N/m;通过图和表可知砝码盘的质量为           g(结果保留两位有效数字,重力加速度取9.8m/s2).

                                                                                    

                                                                                                                               


①竖直;②L3 ,1mm;③Lx;④4.9,10


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质量M=4kg的小车內有一跨过定滑轮的轻绳两端连接小物块m1和m2.如图示,m1=1kg,m2=2kg.m1和固定在小车上的水平轻质弹簧连接.m2由细线OA悬在竖直车壁上的O点.车在水平向右的拉力F作用下在光滑水平面向右做匀加速直线运动.整个装置相对静止.绳AB段水平,BC段竖直.绳OA和竖直方向夹角为45°.弹簧压缩量为10厘米.不计一切摩擦不计定滑轮质量.(g=10m/s2)求:                                                                                  

(1)小车加速度;                                                                                                       

(2)弹簧劲度系数k;                                                                                                 

(3)拉力F大小.                                                                                                       

                                                                          

                                                                                                                                     

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