ÌâÄ¿ÄÚÈÝ
ÈçͼËùʾ£¬Ò»Óй̶¨Ð±ÃæµÄС³µÔÚË®Æ½ÃæÉÏ×öÖ±ÏßÔ˶¯£¬Ð¡Îï¿éÏà¶ÔС³µ¾²Ö¹.СÎï¿éijʱ¿ÌÕý´¦ÓÚͼʾ״̬.ÉèÐ±Ãæ¶ÔÎï¿éµÄÖ§³ÖÁ¦ÎªFN£¬Ð±Ãæ¶ÔÎï¿éµÄĦ²ÁÁ¦ÎªFf£¬¹ØÓÚ´Ëʱ¿ÌÎï¿éµÄÊÜÁ¦Çé¿ö£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ( ¡¡¡¡)
A.ÈôС³µÏò×óÔ˶¯£¬FN¿ÉÄÜΪÁã B.ÈôС³µÏò×óÔ˶¯£¬Ff¿ÉÄÜΪÁã
C.ÈôС³µÏòÓÒÔ˶¯£¬FN²»¿ÉÄÜΪÁã D.ÈôС³µÏòÓÒÔ˶¯£¬Ff²»¿ÉÄÜΪÁã
![]()
BC
(19 ·Ö£©ÈçͼËùʾ£¬Õý·½Ðε¥ÔѾùÔÈÏß¿òabcd,±ß³¤L=0.4m£¬Ã¿±ßµç×èÏàµÈ£¬×ܵç×èR=0.5¦¸¡£ Ò»¸ù×ã¹»³¤µÄ¾øÔµÇáÖÊϸÏß¿ç¹ýÁ½¸öÇáÖʹ⻬¶¨»¬ÂÖ£¬Ò»¶ËÁ¬½ÓÕý·½ÐÎÏß¿ò£¬ÁíÒ»¶ËÁ¬½Ó¾øÔµÎïÌåP,ÎïÌåP·ÅÔÚÒ»¸ö¹â»¬µÄ×ã¹»³¤µÄ¹Ì¶¨Ð±ÃæÉÏ£¬Ð±ÃæÇã½Ç¦È=30¡ã,Ð±ÃæÉÏ·½µÄϸÏßÓëÐ±ÃæÆ½ÐС£ÔÚÕý·½ÐÎÏß¿òÕýÏ·½ÓÐÒ»ÓнçµÄ„òÇ¿´Å³¡£¬Éϱ߽çIºÍϱ߽çII¶¼Ë®Æ½£¬ Á½±ß½çÖ®¼ä¾àÀëÒ²ÊÇL=0.4m¡£´Å³¡·½Ïòˮƽ£¬´¹Ö±Ö½ÃæÏòÀ´Å¸ÐӦǿ¶È´óСB=0.5T¡£ ÏÖÈÃÕý·½ÐÎÏß¿òµÄcd±ß¾àÉϱ߽çIµÄÕýÉÏ·½¸ß¶Èh=0.9mµÄλÖÃÓɾ²Ö¹ÊÍ·Å£¬ÇÒÏß¿òÔÚÔ˶¯¹ý³ÌÖÐʼÖÕÓë´Å³¡´¹Ö±£¬cd±ßʼÖÕ±£³Öˮƽ£¬ÎïÌåPʼÖÕÔÚÐ±ÃæÉÏÔ˶¯£¬Ïß¿ò¸ÕºÃÄÜ ÒÔv =3m/SµÄËٶȽøÈë„òÇ¿´Å³¡²¢ÔÈËÙͨ¹ýÔÈÇ¿´Å³¡ÇøÓò¡£ÊÍ·ÅǰϸÏß±Á½ô£¬ÖØÁ¦¼ÓËÙ¶È g=10m/s2,²»¼Æ¿ÕÆø×èÁ¦¡£
![]()
(1)Ïß¿òµÄcd±ßÔÚÔÈÇ¿´Å³¡ÖÐÔ˶¯µÄ¹ý³ÌÖУ¬c¡¢d¼äµÄµçѹÊǶà´ó£¿
(2)Ïß¿òµÄÖÊÁ¿m1ºÍÎïÌåPµÄÖÊÁ¿m2·Ö±ðÊǶà´ó£¿
(3)ÔÚcd±ß¸Õ½øÈë´Å³¡Ê±£¬¸øÏß¿òÊ©¼ÓÒ»¸öÊúÖ±ÏòϵÄÀÁ¦FʹÏß¿òÒÔ½øÈë´Å³¡Ç°µÄ¼ÓËÙ¶ÈÔȼÓËÙͨ¹ý´Å³¡ÇøÓò£¬Ôڴ˹ý³ÌÖУ¬Á¦F×ö¹¦W=0.23J,ÇóÕý·½ÐÎÏß¿òcd±ß²úÉúµÄ½¹¶úÈÈÊǶàÉÙ£¿