ÌâÄ¿ÄÚÈÝ

ÔÚÓëxÖáÆ½ÐеÄÔÈÇ¿µç³¡ÖУ¬Ò»´øµçÁ¿Îª2¡Á10£­6C¡¢ÖÊÁ¿Îª4¡Á10£­2kgµÄ´øµçÎïÌåÔÚ¾øÔµ¹â»¬Ë®Æ½ÃæÉÏÑØxÖá×öÖ±ÏßÔ˶¯£¬ÆäÎ»ÒÆËæÊ±¼äµÄ±ä»¯¹æÂÉÊÇx£½0.3t£­0.05t2£¬Ê½ÖÐx¡¢t¾ùÓùú¼Êµ¥Î»ÖƵĻù±¾µ¥Î»£®Çó£º
£¨1£©¸ÃÔÈÇ¿µç³¡µÄ³¡Ç¿£»
£¨2£©´Ó¿ªÊ¼Ô˶¯µ½µÚ5sÄ©´øµçÎïÌåËùÔ˶¯µÄ·³Ì£»
£¨3£©ÈôµÚ6sĩͻȻ½«ÔÈÇ¿µç³¡µÄ·½Ïò±äΪ£«yÖá·½Ïò£¬³¡Ç¿´óС±£³Ö²»±ä£¬ÔÚ0¡«8sÄÚ´øµçÎïÌåµçÊÆÄܵÄÔöÁ¿£®
½â£º£¨1£©¼ÓËÙ¶Èa£½£­0.1m/s2 ³¡Ç¿E£½F/q£½ma/q£½4¡Á10£­2¡Á0.1/2¡Á10£­6 N/C£½2¡Á103N/C £¨2£©v0 £½0.3m/s ¼õËÙʱ¼äΪt1£½v0/a£½0.3/0.1s£½3s ´øµçÎïÌåËù¾­¹ýµÄ·³ÌΪs£½x1£«x2£½0.3¡Á3£­0.05¡Á32£«0.1¡Á22/2£½0.65m £¨3£©µÚ6sÄ©´øµçÎïÌåµÄÎ»ÒÆÎª0£¬ µÚ8sÄ©y£½at22/2£½0.1¡Á22/2m£½0.2m ´øµçÎïÌåµçÊÆÄܵÄÔöÁ¿Îª¡÷E£½£­Eqy£½£­2¡Á103¡Á2¡Á10£­6¡Á0.2J£½£­8¡Á10£­4J
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø