ÌâÄ¿ÄÚÈÝ

1£®Ä³Í¬Ñ§ÓÃÈçͼËùʾµÄ×°ÖÃÀ´²â¶¨Ò»Íæ¾ßµç¶¯»úÔÚÎȶ¨×´Ì¬ÏµÄÊä³ö¹¦ÂÊ£®
ʵÑéÆ÷²Ä£ºÍæ¾ßµç¶¯»ú¡¢´øÓÐÁ½¸ö¹Ì¶¨Ìú¼ÐµÄÌú¼Ų̈¡¢µç´Å´òµã¼ÆÊ±Æ÷¡¢µÍѹ½»Á÷µçÔ´¡¢ÖØ´¸¡¢Ï¸Ïß¡¢Ã׳ߡ¢Ö½´ø¡¢¸´Ð´Ö½Æ¬¡¢ÌìÆ½µÈ£®
ʵÑé²½Ö裺

¢ÙÈçͼ1Ëùʾ£¬½«Íæ¾ßµç¶¯»úºÍµç´Å´òµã¼ÆÊ±Æ÷¹Ì¶¨ÔÚÌú¼Ų̈ÉÏ£¬²¢ÓëµçÔ´½ÓºÃ£¬°ÑÒ»¸ùϸÏ߹̶¨Ôڵ綯»úµÄתÂÖÉÏ£¬Ï¸Ïß϶ËÁ¬½ÓÔÚÖØ´¸É϶ˣ¬½«Ö½´øµÄÒ»¶Ë´©¹ý´òµã¼ÆÊ±Æ÷µÄÏÞλ¿×ºó£¬¹Ì¶¨ÔÚÖØ´¸ÉÏ£»
¢ÚÆô¶¯Íæ¾ßµç¶¯»ú´ø¶¯ÖØ´¸ÉÏÉý£¬½Óͨ´òµã¼ÆÊ±Æ÷µçÔ´ÈÃÆä¿ªÊ¼´òµã£»
¢Û¾­¹ýÒ»¶Îʱ¼ä£¬¹Ø±Õ´òµã¼ÆÊ±Æ÷ºÍµç¶¯»ú£¬È¡ÏÂÖ½´ø£¬½øÐвâÁ¿£»
¢ÜÓÃÌìÆ½²â³öÖØ´¸µÄÖÊÁ¿£®
ÒÑÖª½»Á÷µçÔ´ÖÜÆÚT=0.02s£¬Ä³´ÎʵÑé²âµÃÖØ´¸µÄÖÊÁ¿Îª400.0g£¬µÃµ½µÄÖ½´øµÄÒ»¶ÎÈçͼ2Ëùʾ£®
ÊԻشðÏÂÁÐÎÊÌ⣺£¨ÖØÁ¦¼ÓËÙ¶Èg=10.0m/s2£©
£¨1£©ÓÉÖ½´øÉÏ´òϵĵ㣬¿ÉÒÔÅжϸÃʱ¼äÄÚÖØ´¸×öÔÈËÙÖ±ÏßÔ˶¯£»
£¨2£©ÓÉÒÑÖªÁ¿ºÍ²âµÃÁ¿ÇóµÃÍæ¾ßµç¶¯»úµÄÊä³ö¹¦ÂÊP=1.8W£»
£¨3£©ÈôÒÑÖªµç¶¯»úµÄÊäÈëµçѹºãΪ2V£¬Í¨¹ýµç¶¯»úµÄµçÁ÷Ϊ1A£¬Ôòµç¶¯»úµÄÄÚ×èr=0.2?£®

·ÖÎö £¨1£©¸ù¾ÝÖ½´øÉϵĵã¾àµÄ±ä»¯À´È·¶¨Ô˶¯Çé¿ö£»
£¨2£©ÓÉÓÚÎïÌåÔÈËÙÔ˶¯£¬ÖØÁ¦¹¦ÂʵÈÓڵ綯»úÊä³ö¹¦Âʹ¦ÂÊ£¬Òò´Ë¸ù¾Ý¹¦Âʹ«Ê½P=FV¿ÉÒÔÇó³öµç¶¯»úÊä³ö¹¦ÂÊ£»
£¨3£©¸ù¾ÝÄÜÁ¿ÊغãÁгöµç¶¯»úµÄÊäÈ빦ÂÊ¡¢Êä³ö¹¦ÂʺÍÄÚ²¿·¢ÈȵĹØÏµÊ½£¬¼´¿ÉÇóµÃr

½â´ð ½â£º£¨1£©ÒòΪֽ´øÉϸ÷µãÖ®¼äµÄ¼ä¾àÏàµÈ£¬¹ÊÖØ´¸×öµÄÊÇÔÈËÙÖ±ÏßÔ˶¯£®
£¨2£©ÒòÔÈËÙÖ±ÏßÔ˶¯£¬µç¶¯»úµÄ¶¯Á¦Îª£ºF=mg=0.4¡Á10N=4N
6¸ö¼ä¾àΪL=5.40cm=0.0540m£¬Àúʱt=6T=6¡Á0.02=0.12s£¬Òò´ËÆäËÙ¶È´óСΪ£ºv=$\frac{L}{t}$=$\frac{0.054}{0.12}$=0.45m/s
ËùÒÔÊä³ö¹¦ÂÊΪ£ºP=Fv=mgv=4¡Á0.45W=1.8W
£¨3£©ÓÉÄÜÁ¿ÊغãµÃ£ºUI=I2r+P
ÔòµÃ£ºr=$\frac{UI-P}{{I}^{2}}$=$\frac{2¡Á1-1.8}{{1}^{2}}$=0.2£¨¦¸£©
¹Ê´ð°¸Îª£º£¨1£©ÔÈËÙÖ±Ïߣ» £¨2£©1.8£»£¨3£©0.2

µãÆÀ Ã÷ȷʵÑéÔ­Àí£¬ÊìÁ·Ó¦ÓÃÎïÀí»ù±¾¹æÂɽâ¾öʵÑéÎÊÌ⣬עÒâ»ù±¾¹«Ê½µÄÓ¦ÓÃÒªµã£¬È絥λҪͳһ£¬¼°ÊµÑéÎó²î·ÖÎö£¬Ä¦²ÁÊÇʵÑéÎó²îµÄÖØÒªÀ´Ô­Ö®Ò»

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø