题目内容
已知x>1,则x+
的最小值为______.
| 2 |
| x-1 |
∵x>1,
∴y=x+
=(x-1)+
+1≥2
+1(当且仅当x-1=
,即x=
+1时取得“=”),
∴ymin=2
+1.
故答案为:2
+1.
∴y=x+
| 2 |
| x-1 |
| 2 |
| x-1 |
| 2 |
| 2 |
| x-1 |
| 2 |
∴ymin=2
| 2 |
故答案为:2
| 2 |
练习册系列答案
相关题目
题目内容
| 2 |
| x-1 |
| 2 |
| x-1 |
| 2 |
| x-1 |
| 2 |
| 2 |
| x-1 |
| 2 |
| 2 |
| 2 |