题目内容
已知sin(
+
)=
,则cosθ=______.
| π |
| 2 |
| θ |
| 2 |
| 1 |
| 3 |
∵sin(
+
)=cos
=
cosθ=2cos2
-1=2×
-1=-
故答案为:-
| π |
| 2 |
| θ |
| 2 |
| θ |
| 2 |
| 1 |
| 3 |
cosθ=2cos2
| θ |
| 2 |
| 1 |
| 9 |
| 7 |
| 9 |
故答案为:-
| 7 |
| 9 |
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题目内容
| π |
| 2 |
| θ |
| 2 |
| 1 |
| 3 |
| π |
| 2 |
| θ |
| 2 |
| θ |
| 2 |
| 1 |
| 3 |
| θ |
| 2 |
| 1 |
| 9 |
| 7 |
| 9 |
| 7 |
| 9 |