ÌâÄ¿ÄÚÈÝ
ijµØÇøÉÏÄê¶Èµç¼ÛΪ0.8Ôª/(ǧÍß¡¤Ê±)£¬ÄêÓõçÁ¿ÎªaǧÍß¡¤Ê±.±¾Äê¶È¼Æ»®½«µç¼Û½µµ½0.55Ôª£¯(ǧÍß¡¤Ê±)ÖÁ0.75Ôª£¯(ǧÍß¡¤Ê±)Ö®¼ä£¬¶øÓû§ÆÚÍûµç¼ÛΪ0.4Ôª£¯(ǧÍß¡¤Ê±).¾²âË㣬ϵ÷µç¼ÛºóÐÂÔöµÄÓõçÁ¿Óëʵ¼Êµç¼ÛºÍÓû§ÆÚÍûµç¼ÛµÄ²î³É·´±È(±ÈÀýϵÊýΪk).¸ÃµØÇøµçÁ¦µÄ³É±¾¼ÛΪ0.3Ôª£¯(ǧÍß¡¤Ê±).(1)д³ö±¾Äê¶Èµç¼Ûϵ÷ºó£¬µçÁ¦²¿ÃŵÄÊÕÒæyÓëʵ¼Êµç¼ÛxµÄº¯Êý¹ØÏµÊ½£»
(2)Éèk=0.2 A£¬µ±µç¼Û×îµÍ¶¨Îª¶àÉÙʱÈԿɱ£Ö¤µçÁ¦²¿ÃŵÄÊÕÒæ±ÈÉÏÄêÖÁÉÙÔö³¤20%?
¡²×¢:ÊÕÒæ=ʵ¼ÊÓõçÁ¿¡Á(ʵ¼Êµç¼Û-³É±¾¼Û)¡³
½â:(1)Éèϵ÷ºóµÄµç¼ÛΪxÔª£¯(ǧÍß¡¤Ê±)£¬ÒÀÌâÒâÖªÓõçÁ¿ÔöÖÁ
+a£¬µçÁ¦²¿ÃŵÄÊÕÒæÎªy=(
+a)(x-0.3)(0.55¡Üx¡Ü0.75).
(2)ÒÀÌâÒâÓÐ![]()
ÕûÀí,µÃ![]()
½â´Ë²»µÈʽ,µÃ0.60¡Üx¡Ü0.75.
´ð:µ±µç¼Û×îµÍ¶¨Îª0.60Ôª£¯(ǧÍß¡¤Ê±)ʱ£¬ÈԿɱ£Ö¤µçÁ¦²¿ÃŵÄÊÕÒæ±ÈÈ¥ÄêÖÁÉÙÔö³¤20%.
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿