题目内容
已知
=(6,1),
=(x,y),
=(-2,-3),且
∥
,则x+2y的值为( )
| AB |
| BC |
| CD |
| BC |
| DA |
| A.2 | B.0 | C.
| D.-2 |
∵
=
+
+
=(2-x-6,3-y-1)=(-4-x,2-y)
又因为:
∥
?x(2-y)-y(-4-x)=0?x+2y=0.
故选B.
| DA |
| DC |
| CB |
| BA |
又因为:
| BC |
| DA |
故选B.
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已知
=(6,1),
=(x,y),
=(-2,-3),且
∥
,则x+2y的值为( )
| AB |
| BC |
| CD |
| BC |
| DA |
| A、2 | ||
| B、0 | ||
C、
| ||
| D、-2 |