题目内容
已知平行六面体ABCD-A1B1C1D1中,底面ABCD是边长为1的正方形AA1=2,∠A1AB=∠A1AD=120°,则线段AC1的长为( )
A.
| B.
| C.2 | D.
|
∵
=
+
+
,|
|=|
|=1,|
|=2,
•
=0,
•
=|
| |
|cos120°=-1=
•
,
∴
2=(
+
+
)2=
2+
2+
2+2
•
+2
•
+2
•
=1+1+22+0+2×(-1)+2×(-1)=2.
∴|
|=
.
故选A.
| AC1 |
| AD |
| AB |
| AA1 |
| AD |
| AB |
| AA1 |
| AB |
| AD |
| AD |
| AA1 |
| AD |
| AA1 |
| AB |
| AA1 |
∴
| AC1 |
| AD |
| AB |
| AA1 |
| AD |
| AB |
| AA1 |
| AB |
| AD |
| AD |
| AA1 |
| AB |
| AA1 |
=1+1+22+0+2×(-1)+2×(-1)=2.
∴|
| AC1 |
| 2 |
故选A.
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