题目内容
已知f (x+1)=x2-3x+2,则f(
)的解析表达式为______.
| 1 |
| x |
∵f (x+1)=x2-3x+2,令x+1=t,解得x=t-1
∴f (t)=(t-1)2-3(t-1)+2=t2-5t+6
故f (x)=x2-5x+6,
∴f(
)=
-
+6
故答案为:
-
+6
∴f (t)=(t-1)2-3(t-1)+2=t2-5t+6
故f (x)=x2-5x+6,
∴f(
| 1 |
| x |
| 1 |
| x2 |
| 5 |
| x |
故答案为:
| 1 |
| x2 |
| 5 |
| x |
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