题目内容
【题目】如图,在等腰直角△ABO中,设
=
,
=
,|
|=|
|=1,C为AB上靠近A点的三等分点,过C作AB的垂线l,设P为垂线上任一点,
=
,则
(
﹣
)=( ) ![]()
A.![]()
B.﹣ ![]()
C.﹣ ![]()
D.![]()
【答案】B
【解析】解:∵等腰直角△ABO中,设
=
,
=
,|
|=|
|=1, C为AB上靠近A点的三等分点,过C作AB的垂线l,设P为垂线上任一点,
=
,
设AB中点为D,则
=
+
,
=
+
.
∵
⊥
,∴
=
(
﹣
)=0,
∴
(
﹣
)=
(
﹣
)=(
+
)
=
+
=
+0=(
+
)(
﹣
)=
﹣
+
=
﹣
+0=﹣
,
故选:B.
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