题目内容

若A,B,C是圆x2+y2=1上不同的三个点,且
OA
OB
=0
,存在实数λ,μ使得
OC
=λ
OA
OB
,实数λ,μ的关系为(  )
A.λ22=1B.
1
λ
+
1
μ
=1
C.λ•μ=1D.λ+μ=1
OC
OA
OB
,两边平方得:
|
OC
|2=λ2|
OA
2
|+μ2|
OB
|2+2λμ
OA
OB

|
OA
|=|
OB
|=|
OC
|=1

∴λ22=1
故选A
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