题目内容
求函数极限:| lim |
| x→∞ |
| 1 |
| x |
| 1 |
| x2 |
分析:由题意知
=
=0,由此可知
(2-
+
)的值.
| lim |
| n→∞ |
| 1 |
| x |
| lim |
| n→∞ |
| 1 |
| x2 |
| lim |
| x→∞ |
| 1 |
| x |
| 1 |
| x2 |
解答:解:
(2-
+
)=
2-
+
=2.
| lim |
| x→∞ |
| 1 |
| x |
| 1 |
| x2 |
| lim |
| n→∞ |
| lim |
| n→∞ |
| 1 |
| x |
| lim |
| n→∞ |
| 1 |
| x2 |
点评:本题考查函数的极限,解题的关键是正确选用公式.
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