题目内容

已知x3+1=a,a22ax3+x6的值.

答案:
解析:

解法一:a22ax3x6

=(x3122x31x3x6

x62x312x62x3x6

2x62x62x32x31

1

解法二:由x31a

x3a1

x6=(x32=(a12

a22ax3x6

a22aa1)+(a12

[a-(a1]2

=(aa12

1


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