题目内容
已知x-3+1=a,求a2-2ax-3+x-6的值.
答案:
解析:
解析:
解法一:a2-2ax-3+x-6 =(x-3+1)2-2(x-3+1)x-3+x-6 =x-6+2x-3+1-2x-6-2x-3+x-6 =2x-6-2x-6+2x-3-2x-3+1 =1 解法二:由x-3+1=a 得x-3=a-1 x-6=(x-3)2=(a-1)2 ∴a2-2ax-3+x-6 =a2-2a(a-1)+(a-1)2 =[a-(a-1)]2 =(a-a+1)2 =1 |
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