题目内容
公比不为1等比数列{an}的前n项和为Sn,且-3a1,-a2,a3成等差数列,若a1=1,则S4=( )
| A.-20 | B.0 | C.7 | D.40 |
设数列的公比为q(q≠1),则
∵-3a1,-a2,a3成等差数列,
∴-3a1+a3=-2a2,
∵a1=1,∴-3+q2+2q=0,
∵q≠1,∴q=-3
∴S4=1-3+9-27=-20
故选A.
∵-3a1,-a2,a3成等差数列,
∴-3a1+a3=-2a2,
∵a1=1,∴-3+q2+2q=0,
∵q≠1,∴q=-3
∴S4=1-3+9-27=-20
故选A.
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