题目内容
若sinα=
,则cos2α=
.
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分析:利用cos2α=1-2sin2α,即可求得结论.
解答:解:∵sinα=
,∴cos2α=1-2sin2α=1-2×
=
故答案为:
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故答案为:
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点评:本题考查二倍角的余弦,解题的关键是利用cos2α=1-2sin2α,属于基础题.
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