题目内容
| lim |
| x→1 |
| x2-3x+2 |
| x3-4x+3 |
分析：把
等价转化为
，进一步简化为
=1．由此能够求出结果．
| lim |
| x→1 |
| x2-3x+2 |
| x3-4x+3 |
| lim |
| x→1 |
| (x-1)(x-2) |
| (x3-1)-4(x-1) |
| lim |
| x→1 |
| x-2 |
| x2+x-3 |
解答：解：
=
=
=
=1．
故选A．
| lim |
| x→1 |
| x2-3x+2 |
| x3-4x+3 |
=
| lim |
| x→1 |
| (x-1)(x-2) |
| (x3-1)-4(x-1) |
=
| lim |
| x→1 |
| (x-1)(x-2) |
| (x-1)(x2+x-3) |
=
| lim |
| x→1 |
| x-2 |
| x2+x-3 |
故选A．
点评：本题考查函数的极限的求法，是基础题．解题时要认真审题，仔细解答，注意合理地进行等价转化．
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