题目内容
| lim |
| n→∞ |
| 2n2+3n+1 |
| n2+2 |
分析:可将
转化为
,答案可求.
| lim |
| n→∞ |
| 2n2+3n+1 |
| n2+2 |
| lim |
| n→∞ |
2+
| ||||
1+
|
解答:解:∵
=
=2.
故选A.
| lim |
| n→∞ |
| 2n2+3n+1 |
| n2+2 |
| lim |
| n→∞ |
2+
| ||||
1+
|
故选A.
点评:本题考查极限及其运算,着重考查和差积商的极限运算法则,属于基础题.
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