题目内容
设S=1+3(x-1)+3(x-1)2+(x-1)3,S=( )
| A.(x-1)3 | B.(x-2)3 | C.(x+1)3 | D.x3 |
S=1+3(x-1)+3(x-1)2+(x-1)3=
•13+
•12•(x-1)+
•1•(x-1)2+
•(x-1)3=[1+(x-1)]3=x3
故选D.
| C | 03 |
| C | 13 |
| C | 23 |
| C | 33 |
故选D.
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