题目内容
| OA |
| a |
| OB |
| b |
| OP |
| p |
| a |
| b |
| p |
| a |
| b |
分析:因为
-
=
与向量
垂直,得
•(
-
)=
•
=0,因此将向量
表示成
、
的和,从而
•(
-
)=
•(
-
)=
(
+
)(
-
)=
(
2-
2),代入题中的数据即可得到
•(
-
)的值.
| a |
| b |
| BA |
| MP |
| MP |
| a |
| b |
| MP |
| BA |
| OP |
| OM |
| MP |
| p |
| a |
| b |
| OM |
| a |
| b |
| 1 |
| 2 |
| a |
| b |
| a |
| b |
| 1 |
| 2 |
| a |
| b |
| p |
| a |
| b |
解答:
解:连接OM,根据题意得
=
(
+
)=
(
+
)
∵
=
+
=
∴
•(
-
)=(
+
)•(
-
)=
(
+
)(
-
)+
•(
-
)
∵
-
=
,
⊥
,得
•(
-
)=
•
=0
∴
•(
-
)=
(
+
)(
-
)=
(
2-
2)=
(32-22)=
故选:D
| OM |
| 1 |
| 2 |
| OA |
| OB |
| 1 |
| 2 |
| a |
| b |
∵
| OP |
| OM |
| MP |
| p |
∴
| p |
| a |
| b |
| OM |
| MP |
| a |
| b |
| 1 |
| 2 |
| a |
| b |
| a |
| b |
| MP |
| a |
| b |
∵
| a |
| b |
| BA |
| MP |
| BA |
| MP |
| a |
| b |
| MP |
| BA |
∴
| p |
| a |
| b |
| 1 |
| 2 |
| a |
| b |
| a |
| b |
| 1 |
| 2 |
| a |
| b |
| 1 |
| 2 |
| 5 |
| 2 |
故选:D
点评:本题给出三角形的边AB的垂直平分线,求向量的数量积,着重考查了线段垂直平分线的性质、向量的线性运算和数量积运算性质等知识,属于基础题.
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