题目内容

用“<”从小到大排列log23,0.5-14-
3
2
,log0.53
log0.53<4-
3
2
<log23<0.5-1
log0.53<4-
3
2
<log23<0.5-1
分析:根据 2=log24>log23>1,0.5-1= 2 4-
3
2
=
1
23
=
1
8
,log0.53<log0.51=0,可得结论.
解答:解:根据 2=log24>log23>1,0.5-1= 2 4-
3
2
=
1
23
=
1
8
,log0.53<log0.51=0,
可得 log0.53<4-
3
2
<log23<0.5-1
故答案为 log0.53<4-
3
2
<log23<0.5-1
点评:本题主要考查对数函数的单调性和特殊点,属于中档题.
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