题目内容
对于?x∈R+,用F(x)表示log2x的整数部分,则F(1)+F(2)+…+F(1023)=______.
令F(1)+F(2)+…+F(1023)=S,
S=1×2+2×22+3×23+…+9×29
2S=1×22+2×23+3×24+…+8×29+9×210,
S=9×210-210+2=8194
故答案为:8194
S=1×2+2×22+3×23+…+9×29
2S=1×22+2×23+3×24+…+8×29+9×210,
S=9×210-210+2=8194
故答案为:8194
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