题目内容
已知sin(
-α)=-
,
<α<
,则sinα=______.
| π |
| 4 |
| 2 |
| 3 |
| π |
| 4 |
| π |
| 2 |
因为:sin(
-α)=-
,
<α<
,
∴cos(
-α)=
.
∴sinα=sin[
-(
-α)]=sin
•cos(
-α)-cos
•sin(
-α)=
.
故答案为:
.
| π |
| 4 |
| 2 |
| 3 |
| π |
| 4 |
| π |
| 2 |
∴cos(
| π |
| 4 |
| ||
| 3 |
∴sinα=sin[
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| ||||
| 6 |
故答案为:
| ||||
| 6 |
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